Question

A and B can do a piece of work in 8 days, and A alone can do it in 12 days. How long would B take to do

the same work?



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Answer 1

Explanation:

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Answer 2

Explanation:

(A + B)’s 1 day’s work = \frac{1}{12}……….(I)

(B + C)’s 1 day’s work = \frac{1}{8}…….….(II)

(C + A)’s 1 day’s work = \frac{1}{6}……….(III)

On adding,

2(A + B + C)’s 1 day’s work = \frac{1}{12}+\frac{1}{8}+\frac{1}{6} = \frac{2+3+4}{24} = \frac{9}{24}

∴ (A + B + C)’s 1 day’s work = \frac{9}{24\times 2} = \frac{9}{48}……….(IV)

On subtracting (III) from (IV),

B’s 1 day’s work = \frac{9}{48} - \frac{1}{6}

= \frac{9-8}{48} = \frac{1}{48}

∴ B can complete the work in 48 days.

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