Question

A and b can do a piece of work in 8 days b and c can do it in 24 days while c and a can do it in 60/7 days in how many days can c do it alone.

Answer 1

A and B 1 day work is 1/8 (....equa 1)

B and C 1 day work is 1/24 (.....equa 2)

C and A 1 day work is 7/60 (.....equa 3)

(.....equa 1) - (.....equa 2) = 1/8-1/24 = 1/4 ....... to be contiued

So it will take him 63 days to complete

B - C = 1/4 (.....equa 4)

(.....equa 2)+(.....equa 4) = 2B =

Answer 2

$\textbf {Hey there, here is the solution.}$

.............................................................................................

a and b can do the work in 8 days

⇒ 1 day = 1/8 of the work

.

b and c can do the work in 24 days

⇒ 1 day = 1/24 of the work

.

c and a can do the work in 60/7 days

⇒ 1 day = 7/60 of the work

.

Find the amount of work a + b + c can do in a day:

If we put all of them together:

Amount of work 2a + 2b + 2c can do in a day = 1/8 + 1/24 + 7/60 = 17/60

If we half the manpower:

Amount of work a + b + c can do in a day = 41/240 ÷ 2 = 17/120

.

Find the amount of work c can do in a day:

a + b + c = 17/120 of work in a day

a + b = 1/8 of work in a day

c = 17/120 - 1/8 = 1/60 of work in a day

.

Find the number of days needed for c to do it alone:

1/60 = 1 day

60/60 = 1 x 60 = 60 days

.

Answer: C can do the work in 60 days.

.............................................................................................

⭐$\textbf {Cheers}$⭐