A and B can do a piece of work in 8 days which a alone can do it in 12 days in how many days can be alone do the same work
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24 days
A’s one day’s work = \frac{1}{12}
(A + B)’s one day’s work = \frac{1}{8}
∴ B’s one day’s work =
= \frac{1}{8} - \frac{1}{12} = \frac{3-2}{24} = \frac{1}{24}
∴ B alone can do the work in 24 days.
Hence option [B] is the right answer
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