A and B can do a piece of work individually in 12 and 20 days respectively. They work together
for 6 days before A decides to leave. How many days will it take B to complete the work on his
own?
(a) 4
(b) 3
(c) 6
(d) 14
Answers
Answered by
0
Step-by-step explanation:
correct option is 4
hope it is helpful to you
Answered by
0
Answer:
4 Days
Step-by-step explanation:
Time that A takes to do a piece of work = 12 days
Work done by A in 1 day = 1 / 12th of the work
Time that B takes to do the same work = 20 days
Work done by B in one day = 1 / 20th of the work
So,
Work done in first six days = 6(1/12 + 1/20)
= 6(5/60 + 3/60)
= 6(8/60)
= 6 × 2/15
= 12/15
Remaining work = 3/15
Time that B will take to do the work
= 3/15 ÷ 1/20
= 3/15 × 20
= 1/5 × 20
= 4 days
Hope this helps you.
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