Question

A and B can do a piece of work individually in 12 and 20 days respectively. They work together
for 6 days before A decides to leave. How many days will it take B to complete the work on his
own?
(a) 4
(b) 3
(c) 6
(d) 14

Answer 1

Step-by-step explanation:

correct option is 4

hope it is helpful to you

Answer 2

Answer:

4 Days

Step-by-step explanation:

Time that A takes to do a piece of work = 12 days

Work done by A in 1 day = 1 / 12th of the work

Time that B takes to do the same work = 20 days

Work done by B in one day = 1 / 20th of the work

So,

Work done in first six days = 6(1/12 + 1/20)

= 6(5/60 + 3/60)

= 6(8/60)

= 6 × 2/15

= 12/15

Remaining work = 3/15

Time that B will take to do the work

= 3/15 ÷ 1/20

= 3/15 × 20

= 1/5 × 20

= 4 days

Hope this helps you.