Math, asked by Rathoud1234, 4 months ago

A and B can do a task in 12 hours, while B and C can do the same task in 20 hours and C and A can complete the same work in 10 hours. In how many hours will all three of them finish the task working together?

Answers

Answered by Saby123

Solution :

A and B can do a task in 12 hours, while B and C can do the same task in 20 hours and C and A can complete the same work in 10 hours.

So, in 1 hour

A and B does 1/12 th of the entire work

B and C does 1/20th of the entire work

A and C does 1/10th of the entire work

Adding them

2 [ A + B + C ] does 1/12 th + 1/20 th + 1/10th in an hour

=> 2 [ A + B + C ] > 7/30 th of the work in an hour .

=> A , B and C does 7/60th of the entire work in 1 your .

They take 60/7 hours to finish the entire work together

=> 8 (4/7 ) hours

This is the required answer .

_________________________________________

Anonymous: Right explanation

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mere school mei pura bad boys ka group hai

or mei uss group ka leader hu haha..

haha
i am boss in my school
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Anonymous: superb

Answered by Anonymous

$\huge\underline{\underline{\texttt{{Question:}}}}$

A and B can do a task in 12 hours, while B and C can do the same task in 20 hours and C and A can complete the same work in 10 hours. In how many hours will all three of them finish the task working together?

$\huge\underline{\underline{\texttt{{Given:}}}}$

A and B can do a task in 12 hours
B and C can do the same task in 20 hours
A can complete the same work in 10 hours.

$\huge\underline{\underline{\texttt{{To\:Find:}}}}$

how many hours will all three of them finish the task working together = ?

$\huge\underline{\underline{\texttt{{Solution:}}}}$

$\bold{A \: and \: B \: does \: \frac{1}{12}th \: of \: the \: entire \: work } \\$

$\bold{B \: and \: C \: does \: \frac{1}{20}th \: of \: the \: entire \: work } \\$

$\bold{A \: and \: C \: does \: \frac{1}{10}th \: of \: the \: entire \: work } \\$

$\small\bold\red{by \: adding \: them} \\$

$\bold{2(A + B + C) \: does \: \frac{1}{12}th \: + \frac{1}{20}th+ \frac{1}{10}th \: in \: an \: hour} \\$

$\bold{ = 2(A + B + C) > \frac{7}{30}th \: of \: the \: work \: in \: an \: hour} \\$

$\bold{ = A, \: B \: and \: C \: does \: \frac{7}{60}th \: of \: the \: entire \: work \: in \: 1 \: hour } \\$

They take 60/7 hours to finish the entire work together.

$= \frac{60}{7} = 8\frac{4}{7}$

$\star{\boxed{\sf{so \: the \: required \: answer \: is \: 8 \frac{4}{7} }}}$

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Anonymous: Here they work together in a required hours to complete their task: So it work done will be twice that means - 2 × ( A + B + C ).

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A and B can do a task in 12 hours, while B and C can do the same task in 20 hours and C and A can complete the same work in 10 hours. In how many hours will all three of them finish the task working together? ​

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A and B can do a task in 12 hours, while B and C can do the same task in 20 hours and C and A can complete the same work in 10 hours. In how many hours will all three of them finish the task working together?