Question

draw a graph of given polynomial and fin zeroes of x2-2x-15
​

Answer 1

EXPLANATION.

Graph of the equation,

⇒ F(x) = x² - 2x - 15.

As we know that,

⇒ y = x² - 2x - 15.

Factorizes into middle term split, we get.

⇒ y = x² - 5x + 3x - 15.

⇒ y = x(x - 5) + 3(x - 5).

⇒ y = (x + 3)(x - 5).

Zeroes of the polynomial.

⇒ (x + 3)(x - 5) = 0.

⇒ x = -3  and  x = 5.

Put the values in equation, we get.

Put x = -3 in equation, we get.

⇒ y = (-3)² - 2(-3) - 15.

⇒ y = 9 + 6 - 15.

⇒ y = 15 - 15.

⇒ y = 0.

Their Co-ordinates = (-3,0).

Put x = 5 in equation, we get.

⇒ y = (5)² - 2(5) - 15.

⇒ y = 25 - 10 - 15.

⇒ y = 25 - 25.

⇒ y = 0.

Their Co-ordinates = (5,0).

Put x = 0 in equation, we get.

⇒ y = (0)² - 2(0) - 15.

⇒ y = -15.

Their Co-ordinates = (0,-15).

Answer 2

________________________________

$\huge\gray {{\fbox{\tt{Solution}}}}$

________________________________

Graph of the equation :

⇒ F(x) = x² - 2x - 15.

As we know that,

⇒ y = x² - 2x - 15.

Factorizes into middle term split, we get.

⇒ y = x² - 5x + 3x - 15.

⇒ y = x(x - 5) + 3(x - 5).

⇒ y = (x + 3)(x - 5).

Zeroes of the polynomial.

⇒ (x + 3)(x - 5) = 0.

⇒ x = -3  and  x = 5.

Put the values in equation, we get.

Put x = -3 in equation, we get.

⇒ y = (-3)² - 2(-3) - 15.

⇒ y = 9 + 6 - 15.

⇒ y = 15 - 15.

⇒ y = 0.

Their Co-ordinates = (-3,0).

Put x = 5 in equation, we get.

⇒ y = (5)² - 2(5) - 15.

⇒ y = 25 - 10 - 15.

⇒ y = 25 - 25.

⇒ y = 0.

Their Co-ordinates = (5,0).

Put x = 0 in equation, we get.

⇒ y = (0)² - 2(0) - 15.

⇒ y = -15.

Their Co-ordinates = (0,-15).

________________________________

$\gray {{\fbox{\tt{Hope You Got}}}}$

________________________________