A and b can do a work in 12 days and b and c can do a peice of work in 15 days and c and a can do a peice of work in 20 days then in how many days A can do the work alone ???
Answers
Answered by
1
Step-by-step explanation:
A+B(1day
′
s)=
12
1
work
B+C(1day
′
s)=
15
1
work
A+C(1day
′
s)=
20
1
work
Adding all the above,
2(A+B+C)(1day
′
s)=
12
1
+
15
1
+
20
1
=
60
5+4+3
=
60
12
=
5
1
work
∴A+B+C(1day
′
s)=
10
1
work
∴C(1day
′
s)=(A+B+C)(1day
′
s)−(A+B)(aday
′
s)
=
10
1
−
12
1
=
60
6−5
=
60
1
Hence, C can complete the whole work in 60 days.
Answered by
0
A +B+C part of work done in a day = 1/10
Work done per day by A
= A+B+C - (B+C)
= 1/10 -1/15
=1/30
A alone can finish the work in 30 days
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