A and b can doa work in 10 days,b and c in 6 days,a and c in 12 days,then a b and c together can do the work in
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23 days is the right answer
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Step-by-step explanation:
Let total work be 120 units (LCM of 30, 24 and 20).
(A+B)'s one day work = 4 units
(B+C)'s one day work = 5 units
(C+A)'s one day work = 6 units
Adding all three equations and then dividing by 2,
(A+B+C)'s one day work = 7.5 units
A's one day work = 7.5 - 5 = 2.5 units
In 10 days, all three complete 75 units of work. Remaining 45 units can be completed by A in 18 days (at rate of 2.5 units per day).
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