Question

A and B can finish a peice of work in 16 and 12 days respectively. A started the work and worked at it for 2 days. He was then joined by B . Find the total time taken ​

Answer 1

Sorry mam I have no answer

Answer 2

Answer:

A's 1 day work = 1/16

B's 1 day work = 1/12

(As A worked for 2 days alone we'll find work done by A in 2 days by multiplying his one day work by 2)

A's 2 day work = 2x(1/16) =1/8

Remaining work = 1–1/8 =7/8

( Total work is always presumed to be 1 in all such cases )

Now this remaining work will be done by A and B together .

(A+B)'s 1 day work = (1/16) + (1/12) = 7/48

A and B together can do the remaining work in = (7/8)÷(7/48) = 6 days

Total time taken = 6+2 = 8 days ANS