Math, asked by madstuffswithtanveer, 1 month ago

A and B can finish a work in 20 days B alone can do in 15 days They work together for 2 days and then A goes away in how many will B finish the remaining work​

Answers

Answered by Anupk3724
2

Answer:

A and B do a work in 20 days

In other words, the fraction of work done by A and B in 1 day is 1/20

Similarly Fraction of work done by B in 1 day is 1/15

Now A and B work together for 2 days and completed 2/ 20 or 1/10 of work.

Work left is 1- 1/10 =9/10 which B has to do

1/15 of work is done by B in 1 day

So 9/10 of it is completed by B in

9*15/10

135/10=13.5days

Answered by thanvinethra
1

Answer:

13.5 days

Step-by-step explanation:

A and B do a work in 20 days

In other words, the fraction of work done by A and B in 1 day is 1/20

Similarly Fraction of work done by B in 1 day is 1/15

Now A and B work together for 2 days and completed 2/ 20 or 1/10 of work.

Work left is 1- 1/10 =9/10 which B has to do

1/15 of work is done by B in 1 day

So 9/10 of it is completed by B in

9*15/10

135/10=13.5days

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