a and b can together do a piece of work in 10 days. If a works with twice of his efficiency and b works with an efficiency 1/3rd less than his efficiency, then the work gets completed in 6 days. In how many days can a and b do the work alone respectively?
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Answer:
a =8/5
b= 42/5
Step-by-step explanation:
a + b = 10 => a= 10-b
2a + 1b/3 =6
putting above equation in 2nd equation -
2( 10-b ) +1b/3=6
20 - 2b +1b/3 = 6
-2b + 1b/3= 6 -20
(-6b + b)/3 = -14
-5b/3= -14
-5b = -42
b= -42/ -5
b=42/5
putting the value of b in the equation:
a= 10-b
a= 10- 42/5
a = (50- 42)/5
a = 8/5
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