Math, asked by AasthaLuthra9402, 1 year ago

a and b can together do a piece of work in 10 days. If a works with twice of his efficiency and b works with an efficiency 1/3rd less than his efficiency, then the work gets completed in 6 days. In how many days can a and b do the work alone respectively?

Answers

Answered by singhjogi1969
0

Answer:

a =8/5

b= 42/5

Step-by-step explanation:

a + b = 10 => a= 10-b

2a + 1b/3 =6

putting above equation in 2nd equation -

2( 10-b ) +1b/3=6

20 - 2b +1b/3 = 6

-2b + 1b/3= 6 -20

(-6b + b)/3 = -14

-5b/3= -14

-5b = -42

b= -42/ -5

b=42/5

putting the value of b in the equation:

a= 10-b

a= 10- 42/5

a = (50- 42)/5

a = 8/5

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