Question

A and B can together finish a work jn 30 days. they worked at it for 20 days and then B left. the remaining work was done by A alone in 20 more days. in how many days can A alone do it?​

Answer 1

Answer:

total days become 60 because when we take 1 day work ,we reciprocal the no of days given. so when we have to find total no. of days ,we will reciprocal 1 day work

If still any query u can ask

Answer 2

Answer:

60 Days

Step-by-step explanation:

Let $\tt \dfrac{1}{30}$ be the rate they work together in 1 day.

Work done in 20 days:

$\tt \frac{1}{30} \times 20 = \frac{20}{30} = \frac{2}{3}$

Remaining work = 1 - $\tt \frac{2}{3}$ = $\tt \frac{1}{3}$

Now, we can say that A can complete $\tt \frac{1}{3}$ of the work in 20 days.

Thus, to finish the whole work, A can dot it in, (20 x 3) = 60 days.

Stay safe and God bless you!