A and b completed certain work together in 5 days. Had a worked at twice his own speed and b half his own speed, it would have taken them 4 days to complete the job. How much time would it take for a alone to do the job?
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Answer:
10 days
Step-by-step explanation:
Assume work to be done 100%.
First case,
A + B = 1005
= 20% work done per day -------- (1)
Second case,
2A + B2
= 1004
= 25% work done per day ------ (2)
On solving equation (1) and (2), we get
A = 10 days
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