Question

Abc is isosceles triangle right angled at b ,2 equilateral triangle are constructed with base bc and ac prove area of triangle bcd is half of area of triangle acf

Answer 1

Answer:

Yes, very easy .

Step-by-step explanation:

Hypotenuse is likely going to be the longer side .

If you consider AB = a then, BC=a & AC = (√2)*a   [using pythagoras theorem]

Now, equilateral Δ area = (√3)a²/8

So, area of Δ ACF = (√3)a²/4

while area of Δ BCD = (√3)a²/8

SO, area of Δ ACF = (√3)a²/4       :    area of Δ BCD = (√3)a²/8  =    2:1