A and B have 460 coins altogether.If 3/4 of A's number of coins is equal to 2/5 of B's number of coins,find how many coins must B give to A so that they both have equal number of coins.
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according to the question,
3/4 A = 2/5 B -1
A + B = 460 -2
Putting 2 in 1
A = 460 - B
Therefore,
3/4 (460 - B) = 2/5 B
345 - 3/4 B = 2/5 B
2/5 B + 3/4 B = 345
B = 345* 20/23
B = 300
Therefore, from 2 we can get that A = 160
3/4 A = 2/5 B -1
A + B = 460 -2
Putting 2 in 1
A = 460 - B
Therefore,
3/4 (460 - B) = 2/5 B
345 - 3/4 B = 2/5 B
2/5 B + 3/4 B = 345
B = 345* 20/23
B = 300
Therefore, from 2 we can get that A = 160
Anonymous:
plzzz.... mark it as brainliest answer
no.of coins with A = 160
no,of coins with B = 300
there fore B has to give 140 coins to A, to have equal coins with both of them
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3
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