a and b plays a game with numbers. a ask b to choose a two digit number then reverse the digit of the number. a ask b to add them up and divide the number by 11. a guarantees there will no remander left . what was logic behind it?
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Any two digit number can be expressed in the form of 10x+y where x is ten's digit and y is the unit digit.
let 10x+y be the number.
number obtained by reversing its digit will be 10y+x.
when we add both them up,
10x+y+10y+x=11x+11y
when we divide the number by 11,
(11x+11y)/11
=11(x+y)/11
=x+y. since 11 on both sides will be cut.
since x and y are whole numbers because the number is a natural number.
and no fraction is left.
It will exactly be divisible by 11 even if we take any two digit number
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