A and B start from the same point and run around a circular path whose circumstances is 8.4km,at the rate of 1000min and 1400m/min respectively in the opp. Direction.After how much time will they meet each other for the second time?
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Given
FOR A
speed = 1000m/min
circumstances = 8.4 km
time to take one round = 1000/1000 * 8.4
= 1*8.4
= 8.4min
In seconds it take = 8.4*60
=504 sec
FOR B
Speed = 1400 m/min
circumstances = 8.4 km
total time taken to complete one round = 1400/1000*8.4
=1.4*8.4
=11.76 m/min
In seconds = 11.76*60
=705.6 sec
they meet second time = 504/705.6 * 2
= 0.72*2
= 1.44 sec
hope it help you
FOR A
speed = 1000m/min
circumstances = 8.4 km
time to take one round = 1000/1000 * 8.4
= 1*8.4
= 8.4min
In seconds it take = 8.4*60
=504 sec
FOR B
Speed = 1400 m/min
circumstances = 8.4 km
total time taken to complete one round = 1400/1000*8.4
=1.4*8.4
=11.76 m/min
In seconds = 11.76*60
=705.6 sec
they meet second time = 504/705.6 * 2
= 0.72*2
= 1.44 sec
hope it help you
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