a and b take 10 hours to do a job working together, b and c working together take 15 hours while a and c take 20 hours to do the same job how long would each of them take to do the job if they worked alone?
Answers
Answer:
answers is below.
Step-by-step explanation:
time taken by a and b together = 10 hours
time taken by b and c together = 15 hours
time taken by a and c together = 20 hours.
time taken by a and b alone =
10÷2= 5 hours each
time taken by b and c =
15÷2=7.5 hours each
time taken by a and c =
20÷2= 10 hours each
•so, time taken by a=
5 + 10 hours = 15 hours
•Time taken by b=
5 + 7.5 = 12.5 hours
•Time taken by c=
7.5 + 10 = 17.5 hours.
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Step-by-step explanation:
a+b take 10hrs, so 1hr work is 1/10
b+c take 15hrs, so 1hr work 1/15
a+c take 20 hrs, so 1hr work 1/20
2a+2b+2c =1/10 +1/15 + 1/20
=1/4
a+b+c in 1hr is 1/8
a does 1/8 - 1/15= 7/ 120 work in 1hr (a+b+c - (b+c))
a takes 120/7 = 17 1/7 hrs to complete work
b does 1/8 - 1/20= 3/40 work in 1 hr (a+b+c - (a+c))
b takes 13 1/3 hrs to finish the work
c takes 1/8-1/10 = 1/40 work in 1hr (a+b+c - (a+b))
c takes 40hrs to finish the work