A and B take 6hours and 9hours respectively to complete work three work togather
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Answered by
5
Time taken by A to complete the work = 6hrs.
Work done by A in 1 hr. = 1/6.
Time taken by B to complete the work = 9days .
Work done by B in 1 day = 1/9.
Therefore work done by (A + B) in one day = 1/6 + 1/9 = 3+2/18=5/18.
Therefore time taken by A+B to complete the work = 18/5 = days
Work done by A in 1 hr. = 1/6.
Time taken by B to complete the work = 9days .
Work done by B in 1 day = 1/9.
Therefore work done by (A + B) in one day = 1/6 + 1/9 = 3+2/18=5/18.
Therefore time taken by A+B to complete the work = 18/5 = days
Answered by
7
In one hour A completes=1/6 part of the work
In one hour B completes =1/9 part of the work
In one hour they together complete = {(1/6)+(1/9)}
= (6+4)/36
= 10/36
= 5/18 part of the work
5/8 part of the work is completed in 1 hour
So, 1 part of the work is completed in = 8/5
=1+(3/5) hours
So, they together completes the work in 1 whole of 3/5 hours.
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