Math, asked by hello2429, 11 months ago

A and B together can complete a work in 2 days if A alone can do it in 3 days how many days will B required to finish the work if he works alone​

Answers

Answered by sabrinanandini2
0

Heya Answer below

Let number of days taken be B = x

Then work completed by A in day is \frac{1}{3}

Work completed in one day by B is 1/x

Together 1/3

We get,

1/3 + 1/x = 1/2

x+3/3x = 1/2

2x + 6 = 3x

x = 6

Hence B takes 6 days

Answered by snehasunil26
0

Answer:

6 DAYS

Step-by-step explanation:

WORK DONE IN ONE DAY=  1/WORK DONE A PERSON IN X DAYS

1/A+1/B=1/A+B

1/B=1/2-1/3

MULTIPLY 1/2 WITH 3 AND 1/3 WITH 2

1/B=3-1/6

THUS,1/B=1/6

THUS,B CAN COMPLETE THE WORK ALONE IN SIX DAYS

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