Question

A and B together can do a piece of work in 12 days,
which B and C together can do in 16 days. After A
has been working at it for 5 days and B for 7 days,
C finishes in 13 days. In how many days C alone
will do the work?​

Answer 1

Answer:

24 days

48 is lcm of 12 and 16

Answer 2

Hope it helps

Answer:

Work done by (A+B)'s in 1 day= 1/12

work done by (B+C)'s in 1 day= 1/16

Let C does a work in x days

Then work done by C in a day= 1/x

According to the question,

A's 5 day's work+B's 7 day's work+C's 13 day's work=1

(A+B)'s 5 day's+(B+C)'s 2 days+C's 11 day's

5/12+2/15+11/x=1

11/x=1-5/12-2/16

11/x=22/48

x=24days