Question

A and B together can do a piece of work in 62
ays, but B alone can do it in 10 days. How
long will A take to do it alone ?​

Answer 1

Step-by-step explanation:

A'S 1 DAY WORK=1/A

B'S 1DAY WORK=1/B=1/10

TOTAL WORK=1/62

1/A+1/B=1/62

1/A=1/62-1/10

1/A=1/26

A CAN DO IT ALONE IN 26 DAYS.

Answer 2

Answer:

Question is wrongly written , how can it be possible when both are doing in 62 days and B alone can do that work in just 10 days . ?

if we change values than see solution ...

LCM of 10, 62 = 310

efficiency = 31 , 5

A one day work = (31-5) = 26 unit

A takes days to complete whole work = 310/26 = 11(12/13) days .

[ mark as brainlist ]