A and B together can do a piece of work in 62
ays, but B alone can do it in 10 days. How
long will A take to do it alone ?
Answers
Answered by
2
Step-by-step explanation:
A'S 1 DAY WORK=1/A
B'S 1DAY WORK=1/B=1/10
TOTAL WORK=1/62
1/A+1/B=1/62
1/A=1/62-1/10
1/A=1/26
A CAN DO IT ALONE IN 26 DAYS.
Answered by
0
Answer:
Question is wrongly written , how can it be possible when both are doing in 62 days and B alone can do that work in just 10 days . ?
if we change values than see solution ...
LCM of 10, 62 = 310
efficiency = 31 , 5
A one day work = (31-5) = 26 unit
A takes days to complete whole work = 310/26 = 11(12/13) days .
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