A and B together can do a work in 10 days. C can destroy the same work in 28 days. A and B started the work and work for 12 days simultaneously and C started with them for destroying the work for same 12 days. After that A and C leaves and B completes the remaining work in 4 days. In how many days A alone can complete the same work?
Answers
Answer:
After that A and C leaves and B completes the remaining work in 4 days. In how many days A alone can complete the
Given-
No.of days A and B take to complete a work = 10
No.of days C takes to destroys the same work = 28
A, B and C together work for 12 days and then B completes the remaining work in 4 days
To find-
No.of days A alone will take to complete the same work
Solution-
Now,
Work done by A and B in 1 day = 1/10
Work destroyed by C in 1 day = 1/28
Work done by A, B and C = (1/10-1/28)
Work done in 12 days by A,B and C= 12*(1/10-1/28)=216/280
Remaining work is done by B alone in 4 days
Therefore,
Remaining work =1-(216/280)=64/280
B works in 1 day=(64/280)/4=16/280
Hence
A works in 1 day=(1/10-16/280)=12/280
So, A WILL COMPLETE THE WORK IN 280/12 DAYS