A and B together can do e pieu of work in
can finish it in 30 days
In how many days con H alone finish the wook
10 days
while B alone
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Answer:
IN ONE DAY they do:
A + B= 1/30 of the job or A=1/30-B
A + C= 1/20 of the job or A=1/20-C
C + B= 1/24 of the job or C=1/24-B
1/30-B =1/20-1/24 + B
B = (1/30 - 1/20 + 1/24 ) / 2
So B = 1/ 80
Then we find C = 1/24–1/80 = (20 - 6) /480 = 14/480
C = 7/240
then we find A=1/30-B = 1/30 -1/ 80
A = 5 /240
Now with their rendiment in ten days they do together:
= 10 × ( 5/240 + 1/80 + 7/ 240)
= 15/24
What is left to do is by A only is:
1- 15/24 = 3/8 of the job
Since A does 5/ 240 per day we calculate:
X = (3/8) / (5/240)
X= 18
Whic means that after the first days that they work together the job will be finished by A alone in another 18 days.
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