A and B together can finish a work in 15 days. A and C take 2 days more to complete the same work than that of B and C. A, B and C together complete the work in 8 days. In how many days will A finish it separately
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Answer: A completed the work in approximately 13 days
Step-by-step explanation:
Let amount of work done by A = A
Let amount of work done by B = B
Let amount of work done by C = C
Amount of work done by A in one day = 1/A
Amount of work done by B in one day = 1/B
Amount of work done by C in one day = 1/C
According to the question,
1/A + 1/B = 1/ 15 ——— 1.
1/A + 1/C = 1/17 ——— 2.
1/A + 1/B + 1/C = 1/8
Add 1. And 2.
=> 1/A + 1/A + 1/B + 1/C = 1/17 + 1/15
=> 1/A + ( 1/A + 1/B + 1/C ) = 1/17 + 1/15
=> 1/A + 1/ 8 = 1/17 + 1/15
=> 1/A = 1/17 + 1/15 - 1/8 = (120 + 136 - 105) / 2040 = 151/2040
=> A = 2040 / 151
A completed the works in 2040/151 = approximately 13 days
Please brainlist my answer, if helpful!
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