Question

a and b two consecutive negative integers and a^2-b^2=91 find the value of a+b​

Answer 1

Answer:

a^2-b^2=(a+b)(a-b)=91

let a=-x

b=-(x+1)

so

(-x-x-1)(-x+x+1)=91

-2x-1)(1)=91

-2x=92

x=-46

so a=-46 and b=-47

a+b= -46-47= 91