A charge of 3.0×10'6 c is 0.25 m away from a charge of -6.0×10'6 c. a) what is the force on the 3.0 × 10'-6.
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Explanation:
we can solve by coulomb law...
f= 1.296× 10^12 N
by
f= k q1.q2/ r^2
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