Question

A and B walk up an escalator(moving stairway). The escalator moves at a constant speed, A takes six steps for every four of B's steps.A gets to the top of the escalator after having taken 50 steps, while B (because his slower pace lets the escalator do a little more of the work) takes only 40 steps to reach the top. If the escalator were turned off, how many steps would they have to take to walk up?

Answer 1

Answer:

100 is the answer

let total number of stair be n .

let total number of stair be n . according to the prblm A & B RATIO =6:4 and

let total number of stair be n . according to the prblm A & B RATIO =6:4 andno. stairs moved by escalator be "x" (because its speed is constant)

let total number of stair be n . according to the prblm A & B RATIO =6:4 andno. stairs moved by escalator be "x" (because its speed is constant)we can take ratio of A AND ESCALATOR be 6:x

let total number of stair be n . according to the prblm A & B RATIO =6:4 andno. stairs moved by escalator be "x" (because its speed is constant)we can take ratio of A AND ESCALATOR be 6:x50/n-50 = 6/x

let total number of stair be n . according to the prblm A & B RATIO =6:4 andno. stairs moved by escalator be "x" (because its speed is constant)we can take ratio of A AND ESCALATOR be 6:x50/n-50 = 6/x => x = 6(n-50)/50 ........(eq 1)

let total number of stair be n . according to the prblm A & B RATIO =6:4 andno. stairs moved by escalator be "x" (because its speed is constant)we can take ratio of A AND ESCALATOR be 6:x50/n-50 = 6/x => x = 6(n-50)/50 ........(eq 1)same as ratio of B AND ESCALATOR be 4:x

let total number of stair be n . according to the prblm A & B RATIO =6:4 andno. stairs moved by escalator be "x" (because its speed is constant)we can take ratio of A AND ESCALATOR be 6:x50/n-50 = 6/x => x = 6(n-50)/50 ........(eq 1)same as ratio of B AND ESCALATOR be 4:x40/n-40=4/x

let total number of stair be n . according to the prblm A & B RATIO =6:4 andno. stairs moved by escalator be "x" (because its speed is constant)we can take ratio of A AND ESCALATOR be 6:x50/n-50 = 6/x => x = 6(n-50)/50 ........(eq 1)same as ratio of B AND ESCALATOR be 4:x40/n-40=4/x=> x=4(n-40)/40 .........(eq 2)

let total number of stair be n . according to the prblm A & B RATIO =6:4 andno. stairs moved by escalator be "x" (because its speed is constant)we can take ratio of A AND ESCALATOR be 6:x50/n-50 = 6/x => x = 6(n-50)/50 ........(eq 1)same as ratio of B AND ESCALATOR be 4:x40/n-40=4/x=> x=4(n-40)/40 .........(eq 2)after eliminating x we get ,

let total number of stair be n . according to the prblm A & B RATIO =6:4 andno. stairs moved by escalator be "x" (because its speed is constant)we can take ratio of A AND ESCALATOR be 6:x50/n-50 = 6/x => x = 6(n-50)/50 ........(eq 1)same as ratio of B AND ESCALATOR be 4:x40/n-40=4/x=> x=4(n-40)/40 .........(eq 2)after eliminating x we get ,4(n-40)/40 = 6(n-50)/50

let total number of stair be n . according to the prblm A & B RATIO =6:4 andno. stairs moved by escalator be "x" (because its speed is constant)we can take ratio of A AND ESCALATOR be 6:x50/n-50 = 6/x => x = 6(n-50)/50 ........(eq 1)same as ratio of B AND ESCALATOR be 4:x40/n-40=4/x=> x=4(n-40)/40 .........(eq 2)after eliminating x we get ,4(n-40)/40 = 6(n-50)/50=>n=100 Answer