Math, asked by pray7026, 1 year ago

a and b work together complete a task in 30 days.a having work for 16 days b finushes the remaining work alone in 44 days.in hoe many days b alone can finish a work

Answers

Answered by brajmohank94
1

Let A finishes the work in x days

in 1 day, work completed by A = 1/x

In 16 days , work = 16/x work

let B finishes the work in y days

In 44 days work done by B = 44/y work

so,

16/x + 44/y = 1 .........( i )

& 1/x + 1/y = 1/ 30 .......( ii )

eq. ( i ) - ( ii ) x 16

16/x + 44/y - 16/x - 16/y = 1 - 16/30

28/y = 14/30

y = 60

Time taken by B alone = 60 days

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