Question

A and Btogether can do a piece of work in 6 2/3days ,but B alone can do it in 10 days .How long will A take to do it?

Answer 1

A and B unit work=3x/20
B unit work=x/10
A unit work =3x-2x/20=×/20
There fore A will take 20 days alone to complete the work

Answer 2

Let the no. of days taken by A to complete the work be 'x' days

Gn that ,
$\frac{1}{x} + \frac{1}{10} = \frac{3}{20}$
$\frac{10 + x}{10x} = \frac{3}{20}$
$200 + 20x = 30x$
$10x = 200$
$x = 20$


Thus A can finish the work alone in 20 days