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can a polyhedron have 10 faces, 2o edges
15 vertices? give reason.
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By Euler's formula for a polyhedron, Vertices (V) - Edges (E) + Faces (F) =2 Here, Faces (F) = 10; Vertices (V) = 15 and Edges (E) = 20 Thus, 15 - 20 + 10 = 5, which does not satisfy the Euler's formula. Hence, a polyhedron cannot have 10 faces, 20 edges and 15 vertices
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