A AND N ARE THE CENTRES OF THE WHEELS OF THE TOY TRACTOR SHOWN IN THE FIGURE.HOW MANY TIMES WOUKD HAVE THE FRONT WHEEL OF THE TRACTOR ROTATED BY THE TIME THE REAR WHEEL COMPLETES ONE ROTATION?
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Given diameter of front wheels(2r)=80cm⇒r=40cm
diameter of rear wheels(2r)=2m⇒r=1m=100cm
In one revolution area covered is =2πr
∴ Distance covered by front wheel in 1400 revolutions =1400×2π(40)
Let us assume that to cover same distance rear wheel will take x revolutions=x×2π(100)
As both wheel will cover same distance ∴1400×2π(40)=x×2π(100)
x=
100
1400×40
=560
That means rear wheel will make 560 revolutions to cover the required distance.
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