Chemistry, asked by sukhadawani4071, 11 months ago

A aromatic compound A treatment with chcl3/koh

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Answered by mukundisvirat
2

It is given that compound‘C’having the molecular formula,C6H7Nis formed by heating compound ‘B’ with Br2 and KOH. This is aHoffmannbromamidedegradation reaction. Therefore, compound ‘B’ is an amide and compound‘C’is an amine. The only amine having the molecular formula, C6H7Nis aniline, (C6H5NH2). Therefore, compound ‘B’ (from which’C’is formed) must bebenzamide, (C6H5CONH2). Further, benzamide is formed by heating compound ‘A’ with aqueous ammonia. Therefore, compound ‘A’ must be benzoic acid.

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Answered by harshbeerkaur4
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Answer:

❤️❤️It is given that compound‘C’having the molecular formula,C6H7Nis formed by heating compound ‘B’ with Br2 and KOH. This is aHoffmannbromamidedegradation reaction. Therefore, compound ‘B’ is an amide and compound‘C’is an amine. The only amine having the molecular formula, C6H7Nis aniline, (C6H5NH2). Therefore, compound ‘B’ (from which’C’is formed) must bebenzamide, (C6H5CONH2). Further, benzamide is formed by heating compound ‘A’ with aqueous ammonia. Therefore, compound ‘A’ must be benzoic acid.❤️❤️

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