Question

a/(ax−1)+b/(bx−1)=a+b, where a+b≠0, ab≠0

Answer 1

Answer:

/(ax−1)+b/(bx−1)=a+b, where a+b≠0, ab≠0

Step-by-step explanation:

a, b, c, x are real numbers such that abc #0

and

bx + (1 - x)c_cx + (1 - i)a ax + (1 - 1)

prove that, a +b+c= 0 or a = b=c. (INMO 2000