Question

Q: 9 A bag contains balls with odd numbers from 1 to 11. A card is drawn at random, find the probability that the ball is chosen is of:
a) an even number
b) a number 11​

Answer 1

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Q) A bag contains balls with odd numbers from 1 to 11 . A card is drawn at random, find the probability that the ball is cosen of :

a) an even number.

b) a number 11

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• Probability : It means possibility of occurrence of any particular event. It may range from 0 to 1 .

• Probability of an event is unit less.

• In this question, we are given with balls, which are numbered from 1 to 11 , but only balls with odd numbers are taken.

• In this question, we would first find the favorable outcomes that satisfies the given conditions and then divide it from the total number of outcomes.

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For both the cases,

The balls numbered 1 , 3 , 5 , 7 , 9 and 11 would be taken

so,

Total Outcomes = 6

a) an even number.

Since we have taken the balls which have odd numbers so,

• Favorable Outcomes = 0

$\mapsto \sf \: probability _{event} = \dfrac{favorable \: outcomes}{total \: outcomes }$

$\mapsto \sf \: p _{even \: number} = \dfrac{0}{6}$

$\mapsto \: \boxed{ \tt { \pink{p _{even \: number} = \green{ \bf{0}}}}}$

b) a number 11 .

Since only the ball which is numbered 11 is taken so,

• Favorable outcomes = 1

$\mapsto \boxed { \tt \purple{ p _{11} = \red{ \bf \frac{1}{6} }}}$

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Answer 2

Step-by-step explanation:

5 balls (1,3,5,7,9) have odd numbers, out of 10 balls (1,2,3,4,5,6,7,8,9,10) total.

Probability of picking odd number = 5/10 = 1/2 = 0.5 = 50%.

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