A+b=10,ab=21 find a³+b³
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shadowsabers03:
370 is the answer.
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6
sorry for some errors..... but the answer is 370
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a³+b³= (a +b)³ - 3ab(a+b)
= (10)³ - 3×21(10)
= 1000 - 63(10)
= 1000 - 630
= 370
Hence, 370 is the required value....
= (10)³ - 3×21(10)
= 1000 - 63(10)
= 1000 - 630
= 370
Hence, 370 is the required value....
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