Question

a+b=10,
ab =24
the
value
of
ti
a3 +b3​

Answer 1

Answer:

sum of zeroes = b/a

a+b =b/a

10 =b/a

product of zeroes = c/a

ab = c/a

24= c/a

a=1,b= 10,c=24

equation

axsquare - bx+ cx = 0

xsq - 10x + 24 = 0

xsq - (6x +4x) + 24 = 0

xsq-6x-4x+24=0

x(x-6)-4(x-4) =0

(x-4) (x-6)=0

either x=4 or x=6

a = 6,b = 4

a3-b3=

=6×6×6-4×4×4

=216-64

=152