a+b=11,ab=28 find the value of a 3 +b 3
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a3 + b3= (a + b)(a2 ab +b2)
= 11(a2 28 +b2)
=11a2-(28 X 11) +11b2
= 11(a2 + b2) 308
= 11[(a + b)2-2ab]-308
=11[(11)2-2 X 28]-308
=11(121-56)-308
= 11(65)-308
=715-308
= 407
hope it helps ....plz mark as brainliest
= 11(a2 28 +b2)
=11a2-(28 X 11) +11b2
= 11(a2 + b2) 308
= 11[(a + b)2-2ab]-308
=11[(11)2-2 X 28]-308
=11(121-56)-308
= 11(65)-308
=715-308
= 407
hope it helps ....plz mark as brainliest
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