Question

A+B=11 ,B (A+C)=72 ,A+C=8 , A (A+C+B÷3) = ?

Answer 1

A+B=11
B(A+C)=72
A+C=8
B×8=72
B=9
A+B=11
A+9=11
A=2
So A(A+B+C÷3)=54

Answer 2

A + C = 8
then
B ( A+ C) = 72
B (8) = 72
B = 72/8
B = 9

So
A ( A+C +B /3)
= A ( 72+9 /3)
A ( 81/3)
Now
A = 11-B
A = 11-9
A = 2

so
= 2 * 27
= 54