Question

|A+B|=12,A+B=16and theta=60 find|A| and |B|​

Answer 1

Answer:

so.

144 = A.^2 + B^2 + 2AB × 1/2

144 = A square + B square + AB

now as A+ B = 16

so A = 16-B

this means

144 = 16-B square + B square + 2×(16- B) ×B

solve B from here and put the value of B in A+ B = 16 and get the value of A

Answer 2

Answer:

A=14& B=-2

i think this is the answer

explanation: A+B=12-------(1)

A-B=16----(2)

(1)+(2)

A+B=12+

A-B=16

SO

B get cancel

then

2A=12+16

A=28÷2=14

by substuting A in any of the eqn we will get B also