A+B=15 B×C=84 C÷4=3 B+D=18
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Solution: taking equation (3) by cross multiplication we get
(3)C=4*3=12
put the value of C=12 in equation (2) we have
(2)B*C=12; B*12=84; therefore B=84/12=7
now put the value of B=7 in equation (1) we have
(1)A+B=15;A+7=15; therefore A=15–7=8
finally for the required value of D we get:
(4)B+D=18;7+D=18; hence D=18–7=11 answer
Step-by-step explanation:
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