A+B=16,A-B=8 then A=
how much
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Answered by
13
a+b=16
a-b=8
from first eq a=16-b putting a in eq 2 we get
a-b=8
16-b-b=8
-2b=-8 (-ve sign get cancled)
2b=8
b=4 now putting b=4 in 1 eq we will get
a+b=16
a+4=16 a=12,b=4
a-b=8
from first eq a=16-b putting a in eq 2 we get
a-b=8
16-b-b=8
-2b=-8 (-ve sign get cancled)
2b=8
b=4 now putting b=4 in 1 eq we will get
a+b=16
a+4=16 a=12,b=4
Answered by
3
Value of A = 12 from given equation A + B = 16 & A – B = 8
Solution:
Given: A + B = 16_______ (1)
A – B = 8_______ (2)
The above two equations represent a situation which tells that A>B because the difference of A and B is positive which is only possible if A>B.
In order to solve such kind of equations we add the both of the equations and then by adding the two equations we eliminate B and we get A
Adding (1) and (2) we get
2A = 24
A = 12
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