Question

(a-b)^2-16(a-b)+60 factor it by trinomial method

Answer 1

Answer:

Correct option is

A

(y−6)(y−10)

In the given polynomial y

2

−16y+60,

The first term is y

2

and its coefficient is 1.

The middle term is −16y and its coefficient is −16.

The last term is a constant term 60.

Multiply the coefficient of the first term by the constant 1×60=60.

We now find the factor of 60 whose sum equals the coefficient of the middle term, which is −16 and then factorize the polynomial y

2

−16y+60 as shown below:

y

2

−16y+60

=y

2

−10y−6y+60

=y(y−10)−6(y−10)

=(y−6)(y−10)

Hence, y

2

−16y+60=(y−6)(y−10).