Math, asked by krex5567, 5 months ago

(a - b)^2 - 5 (a - b) + 6​

Answers

Answered by Nivedita4209
1

Answer:

(a-b)^2–5(a-b)+6

Let (a-b)=x then,

=x^2-5x+6

=x^2–(3+2)x+6. [By factorising]

=x^2-3x-2x+6

=x(x-3)-2(x-3)

=(x-3)(x-2)

Putting the value of x then,

=(a-b-3)(a-b-2).

Therefore, answer=(a-b-3)(a-b-2).

Answered by jayaswami6878
1

Answer:

a-b)^2–5(a-b)+6 Let (a-b)=x then, =x^2-5x+6 = x^2–(3+2)x+6. [By factorising] =x^2-3x-2x+6 =x (x-3)-2(x-3) =(x-3)(x-2), Putting the value of x then,

=(a-b-3)(a-b-2).

Therefore, answer=(a-b-3)(a-b-2)

Similar questions