(a+b)² x 2-hable - Ca-b)2
(a-b) 2 = 0
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I know the answer is = 4ab, but if I could explain it…
Use the perfect square formula for each of the two expressions (a + b )² = a² + 2ab + b²
So, (a+b)² becomes a² + 2ab + b²
And, (a-b)² becomes a² - 2ab + b²
Since we are simplifying we use the distributive property method. So distribute the parentheses () in one of the expressions.
Don’t forget we are subtracting -,
thus we have the expression, a² + 2ab + b² - (a² - 2ab + b²)
Distribute the - sign in the parentheses ().
Group like terms - a² +a² + 2ab + 2ab -b²+b²
Cancel out -a²+a² and -b²+b²
Therefore∴ , 2ab + 2ab = 4ab
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Answer:
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