a÷b=(3/2)^2×(2/3)-4 find the value of (a÷b)-3
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Answered by
0
Answer:
The given equations are
2
a
+3
b
=17 .....(i)
2
a+2
−3
b+1
=5 ...(ii)
⟹2
a
×2
2
−3
b
×3=5
⟹4×2
a
−3×3
b
=5
We put 2
a
=x & 3
b
=y.
Then the equations become
x+y=17 ...........(iii) &
4x−3y=5 ........(iv).
(iii)×4⟶4x+4y=68.....(v).
(iv)−(v)⟶7y=63
⟹y=9=3
2
.
∴3
b
=3
2
⟹b=2.
Again putting y=9 in
Answered by
1
Step-by-step explanation:
it is so difficult sum
I can not solve it
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