(a-b)^3-4(a-b) factorise it
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Solution:
(a-b)³-4(a-b)
Take (a-b) common, we get
= (a-b)[(a-b)²-4]
= (a-b)[(a-b)²-2²]
=(a-b)(a-b+2)(a-b-2)
/* we know the algebraic identity:
x²-y² = (x+y)(x-y) */
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