(a+b)³-a-b factorise
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Sol : ( a + b )³ - a - b
= ( a + b )³ - ( a + b )
By taking ( a + b ) as common,
= ( a + b ) { ( a + b )² - 1 }
= ( a + b ) ( a² + b² + 2 ab - 1 ) [ ( a + b )² = a² + b² + 2 ab ]
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