Math, asked by Sambhrant05, 10 months ago

(a-b)^3 + (b-c)^3 + (c-a)^3​

Answers

Answered by AdityaKarmokar
1

Answer:

[a^3-b^3-3(ab)(a+b)]+(replace a with b and b with c)+(replace a with c and b with a)

Step-by-step explanation:

(a-b)^3= a^3-b^3-3(ab(a+b)

Answered by mathsismypassion
1

Answer:

We know that, when x + y + z = 0

Then, x^3 + y^3 +z^3 = 3xyz

Now, ( a-b) + ( b-c) + (c-a) = 0

So, ( a-b) ^3 + ( b-c) ^3 + (c-a) ^3 =

3 ( a-b) ( b-c) ( c-a).

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