Question

Number of multiples of 3 between 100 and 199 that are odd numbers?

Answer 1

Step-by-step explanation:

n=?

AP=102,105.......198

a=102

d=3

an=198

an=a+(n-1)d

198=102+(n-1)3

198-102=(n-1)3

96=(n-1)3

96/3=(n-1)

32=(n-1)

n=33